Arrange the following fractions in descending order.

(I) $\frac{5}{9}$

(II) $\frac{7}{11}$

(III) $\frac{8}{15}$

(IV) $\frac{11}{17}$

Question

Arrange the following fractions in descending order. (I) $\frac{5}{9}$ (II) $\frac{7}{11}$ (III) $\frac{8}{15}$ (IV) $\frac{11}{17}$

Accepted Answer

D - (IV) > (II) > (I) > (III). As decimals: I = 5/9 = 0.556, II = 7/11 = 0.636, III = 8/15 = 0.533, IV = 11/17 = 0.647. Descending order is therefore IV, II, I, III.

Answer

A - (I) > (II) > (III) > (IV)

Answer

B - (I) > (III) > (IV) > (II)

Answer

C - (IV) > (II) > (III) > (I)

Arrange the following fractions in descending order. (I) \(\frac{5}{9}\) (II) \(\frac{7}{11}\) (III) \(\frac{8}{15}\) (IV) \(\frac{11}{17}\)

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