Site navigation

If one of the roots of quadratic equation 7x² - 50x + k = 0 is 7, then what is the value of k?

Substituting the root \(x = 7\) into \(7x^2 - 50x + k = 0\) gives \(7(49) - 50(7) + k = 0 \implies 343 - 350 + k = 0 \implies k = 7\).

Choose your answer

If one of the roots of quadratic equation 7x² - 50x + k = 0 is 7, then what is the value of k?

Select one answer
Answer and explanation

Correct answer A

Substituting the root x=7x = 7 into 7x2−50x+k=07x^2 - 50x + k = 0 gives 7(49)−50(7)+k=0  ⟹  343−350+k=0  ⟹  k=77(49) - 50(7) + k = 0 \implies 343 - 350 + k = 0 \implies k = 7.

Practice for these exams

  • Rajasthan Headmaster

Related question papers

Related questions in this topic