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Which of the following numbers is divisible by \(3^{10} + 2\)?

Question and options

Which of the following numbers is divisible by 310+23^{10} + 2?
  1. 320+43^{20} + 4
  2. 330+23^{30} + 2
  3. 320+83^{20} + 8
  4. 330+83^{30} + 8

Answer and explanation

Correct answer: D - \(3^{30} + 8\)
Let t = 3^10, so t = -2 mod (t+2). Then t^3 + 8 = -8 + 8 = 0 mod (t+2). The others leave remainders 8, -6 and 12.

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  • IPMAT Indore

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