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Sum of squares of three positive numbers is 608 and they are in the ratio 2 : 3 : 5. Then find the numbers

Question and options

Sum of squares of three positive numbers is 608 and they are in the ratio 2 : 3 : 5. Then find the numbers
  1. 6, 9, 15
  2. 8, 12, 20
  3. 10, 15, 25
  4. 14, 21, 35

Answer and explanation

Correct answer: B - 8, 12, 20
Take 2k,3k,5k2k, 3k, 5k: 4k2+9k2+25k2=38k2=6084k^2 + 9k^2 + 25k^2 = 38k^2 = 608, so k2=16k^2 = 16 and k=4k = 4. The numbers are 8, 12, 20.

Practice for these exams

  • CUSAT CAT LLM

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