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The two benzylic hydrogens \(\mathrm{H_A}\) and \(\mathrm{H_B}\) in the compounds I and II are

Question and options

The two benzylic hydrogens HA\mathrm{H_A} and HB\mathrm{H_B} in the compounds I and II are
Figure
  1. diastereotopic in I and enantiotopic in II
  2. homotopic in I and enantiotopic in II
  3. diastereotopic in both I and II
  4. enantiotopic in both I and II

Answer and explanation

Correct answer: B - homotopic in I and enantiotopic in II
In diphenylmethane (I) the two benzylic H are interchanged by a C2C_2 axis, so they are homotopic. In phenyl(3-pyridyl)methane (II) there is no C2C_2 axis but a mirror plane relates them, so they are enantiotopic.

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