The remainder when \((29^{29})^{29}\) is divided by \(9\) is
Question and options
The remainder when is divided by is
- 1
- 2
- 3
- 4
Answer and explanation
Correct answer: B - 2
29 = 2 mod 9 and exponent is 29*29 = 841. 2^6 = 1 mod 9 and 841 = 1 mod 6, so remainder = 2^1 = 2.
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IPMAT Indore
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