If \(x+y+z=7\), \(x^2+y^2+z^2=85\) and \(x^3+y^3+z^3=913\), then value of \(\sqrt[3]{xyz}\) is
Question and options
If , and , then value of is
- 1
- 2
- 4
- 8
Answer and explanation
Correct answer: C - 4
xy+yz+zx = (49-85)/2 = -18. x^3+y^3+z^3-3xyz = 7(85+18) = 721, so 3xyz = 913-721 = 192, xyz = 64, cube root = 4.
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