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The present ages of three persons are in the proportion 4 : 7 : 9. Eight years ago, the sum of their ages was 56. Find their present ages (in years)

Question and options

The present ages of three persons are in the proportion 4 : 7 : 9. Eight years ago, the sum of their ages was 56. Find their present ages (in years)
  1. 8, 20, 28
  2. 16, 28, 36
  3. 20, 35, 45
  4. 15, 20, 35

Answer and explanation

Correct answer: B - 16, 28, 36
Ages 4k,7k,9k4k, 7k, 9k; sum 8 years ago =20k−24=56= 20k - 24 = 56, so k=4k = 4. Ages 16, 28, 36.

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