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In a triangle ABC, let D be the midpoint of BC, and AM be the altitude on BC. If the lengths of AB, BC and CA are in the ratio of 2:4:3, then the ratio of the lengths of BM and AD would be

Question and options

In a triangle ABC, let D be the midpoint of BC, and AM be the altitude on BC. If the lengths of AB, BC and CA are in the ratio of 2:4:3, then the ratio of the lengths of BM and AD would be
  1. 11:41011:4\sqrt{10}
  2. 12:1112:11
  3. 11:1211:12
  4. 410:114\sqrt{10}:11

Answer and explanation

Correct answer: A - \(11:4\sqrt{10}\)
Take AB=2, BC=4, CA=3. BM = (AB^2+BC^2-CA^2)/(2BC) = (4+16-9)/8 = 11/8. Median AD^2 = (2*4+2*9-16)/4 = 10/4, AD = sqrt10/2. BM:AD = (11/8)/(sqrt10/2) = 11:4sqrt10.

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  • IPMAT Indore

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