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The number of pairs \((x, y)\) satisfying the equation \(\sin x + \sin y = \sin(x + y)\) and \(|x| + |y| = 1\) is

Question and options

The number of pairs (x,y)(x, y) satisfying the equation sin⁡x+sin⁡y=sin⁡(x+y)\sin x + \sin y = \sin(x + y) and ∣x∣+∣y∣=1|x| + |y| = 1 is
  1. 6
  2. 4
  3. 3
  4. 2

Answer and explanation

Correct answer: A - 6

There are 66 ordered pairs. The sine equation factors as 4sin⁡x2sin⁡y2sin⁡x+y2=04\sin\frac{x}{2}\sin\frac{y}{2}\sin\frac{x+y}{2}=0, and the bounds give x=0x=0, y=0y=0, or x+y=0x+y=0. Each line meets ∣x∣+∣y∣=1|x|+|y|=1 at two distinct points, giving four axis points and two more when x+y=0x+y=0. Counting just the axes gives 44.

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  • IPMAT Indore

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