The expression 2x3 + ax2 + bx + 3, where a and b are constants, has a factor of x-1 and leaves a remainder of 15 when divided by x + 2. Then, (a, b) =
Question and options
The expression 2x3 + ax2 + bx + 3, where a and b are constants, has a factor of x-1 and leaves a remainder of 15 when divided by x + 2. Then, (a, b) =
- (-3,8)
- (3,-8)
- (-3,-8)
- (3, 8)
Answer and explanation
Correct answer: B - (3,-8)
f(1) = 2+a+b+3 = 0 gives a+b = -5. f(-2) = -16+4a-2b+3 = 15 gives 2a-b = 14. Solving: a = 3, b = -8.
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