Placing which of the following two digits at the right end of \(4530\) makes the resultant six digit number divisible by \(6, 7\) and \(9\):
Question and options
Placing which of the following two digits at the right end of makes the resultant six digit number divisible by and :
- 96
- 78
- 42
- 54
Answer and explanation
Correct answer: A - 96
Need divisibility by LCM(6,7,9) = 126. 453000 mod 126 = 30 (126*3595 = 452970), so the last two digits must be 126-30 = 96; 453096 = 126*3596.
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IPMAT Indore
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