The number of triangles that can be formed by choosing points from 7 points on a line and 5 points on another parallel line is

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Correct answer: C - 175

There are $175$ triangles. A triangle uses two points on one line and one on the other, giving $\binom72\cdot5+\binom52\cdot7=105+70$ . The count $220=\binom{12}3$ includes triples that lie on one line.

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