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Match List I with List II List-I (Expression)List-II (Absolute Value) (A) \[\sqrt{15 \times 163 \div 5-89}\] (I) 105 (B) \[\sqrt{15^{2}+11 \times 3^{2}}\] (II) 20 (C) \[\sqrt{8^{2} \times 7 \times…

Question and options

Match List I with List II
List-I (Expression)List-II (Absolute Value)
(A)15×163÷5−89\sqrt{15 \times 163 \div 5-89}(I)105
(B)152+11×32\sqrt{15^{2}+11 \times 3^{2}}(II)20
(C)82×7×52−175\sqrt{8^{2} \times 7 \times 5^{2}-175}(III)10
(D)91+70+121\sqrt{91+\sqrt{70+\sqrt{121}}}(IV)18


Choose the correct answer from the following options:
  1. (A) with (III), (B) with (I), (C) with (IV), (D) with (II)
  2. (A) with (II), (B) with (III), (C) with (I), (D) with (IV)
  3. (A) with (II), (B) with (IV), (C) with (I), (D) with (III)
  4. (A) with (IV), (B) with (III), (C) with (II), (D) with (I)

Answer and explanation

Correct answer: C - (A) with (II), (B) with (IV), (C) with (I), (D) with (III)
(A) sqrt(489-89) = sqrt(400) = 20 (II). (B) sqrt(225+99) = sqrt(324) = 18 (IV). (C) sqrt(11200-175) = sqrt(11025) = 105 (I). (D) sqrt(91 + sqrt(81)) = sqrt(100) = 10 (III).

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