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If highest common factor of \(x^{2}-p x-q\) and \(5 x^{2}-3 p x-15 q\) is \((x-3)\), then value of ( \(\left.p, q\right)\) will be :

Question and options

If highest common factor of x2−px−qx^{2}-p x-q and 5x2−3px−15q5 x^{2}-3 p x-15 q is (x−3)(x-3), then value of ( p,q)\left.p, q\right) will be :
  1. (53,4)\left(\frac{5}{3}, 4\right)
  2. (−53,−4)\left(\frac{-5}{3},-4\right)
  3. (52,32)\left(\frac{5}{2}, \frac{3}{2}\right)
  4. (4,−35)\left(4, \frac{-3}{5}\right)

Answer and explanation

Correct answer: C - \(\left(\frac{5}{2}, \frac{3}{2}\right)\)
x=3 is a root of both: 9-3p-q = 0 and 45-9p-15q = 0, i.e. 3p+q = 9 and 3p+5q = 15. Then 4q = 6, so q = 3/2 and p = 5/2.

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