If $\alpha$ and $\beta$ are the roots of the equation $a x^{2}+b x+c=0$ , then value of

$\frac{1}{a \alpha+b}+\frac{1}{a \beta+b}$ is :

Question

If $\alpha$ and $\beta$ are the roots of the equation $a x^{2}+b x+c=0$, then value of $\frac{1}{a \alpha+b}+\frac{1}{a \beta+b}$ is :

Accepted Answer

B - $\frac{\mathrm{b}}{\mathrm{ac}}$. From a*alpha^2 + b*alpha + c = 0 we get a*alpha + b = -c/alpha, and likewise for beta. The sum = -(alpha+beta)/c = -(-b/a)/c = b/(ac).

Answer

A - $\frac{a}{b c}$

Answer

C - $\frac{c}{a b}$

Answer

D - $\frac{1}{a b c}$

If \(\alpha\) and \(\beta\) are the roots of the equation \(a x^{2}+b x+c=0\), then value of \(\frac{1}{a \alpha+b}+\frac{1}{a \beta+b}\) is :

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