If $A=\left[\begin{array}{ll}1 & 0 \ \frac{1}{2} & 0\end{array}\right]$ then $A^{2022}$ is

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D - None of the given options is correct. A^2 = [[1,0],[1/2,0]] = A, so A is idempotent and A^2022 = A = [[1,0],[1/2,0]]. None of the listed matrices equals this, so none of the given options is correct.

Answer

A - $\left[\begin{array}{cc}1 & 0 \ \frac{1}{2^{2022}} & 0\end{array}\right]$

Answer

B - $\left[\begin{array}{cc}1 & 0 \ 1011 & 0\end{array}\right]$

Answer

C - $\left[\begin{array}{cc}1 & 0 \ 2022 & 0\end{array}\right]$

If \(A=\left[\begin{array}{ll}1 & 0 \\ \frac{1}{2} & 0\end{array}\right]\) then \(A^{2022}\) is

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