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Let \(a, b, c, d, e, f, g\) be seven consecutive even numbers and \(j, k, l, m, n\) be five consecutive odd numbers. What is the average of all numbers?

Question and options

Let a,b,c,d,e,f,ga, b, c, d, e, f, g be seven consecutive even numbers and j,k,l,m,nj, k, l, m, n be five consecutive odd numbers. What is the average of all numbers?
  1. 3(a+n)2\dfrac{3(a+n)}{2}
  2. (5l+7d12)\left(\dfrac{5l+7d}{12}\right)
  3. (a+b+m+n4)\left(\dfrac{a+b+m+n}{4}\right)
  4. (a+n12)\left(\dfrac{a+n}{12}\right)

Answer and explanation

Correct answer: B - \(\left(\dfrac{5l+7d}{12}\right)\)
Seven consecutive evens have mean d (sum 7d); five consecutive odds have mean l (sum 5l). Average of all 12 numbers = (7d+5l)/12.

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