If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same work in 2 days, then what is the time taken by 15 men and 20 boys to complete the same type of work?

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A - 4 days. Let one man do $m$ and one boy $b$ per day: $6m + 8b = \frac{1}{10}$ and $26m + 48b = \frac{1}{2}$. Multiplying the first by 6 gives $36m + 48b = 0.6$; subtracting, $10m = 0.1$, $m = 0.01$, then $b = 0.005$. $15m + 20b = 0.15 + 0.10 = 0.25$ per day, so…

Answer

B - 5 days

Answer

C - 6 days

Answer

D - 7 days

If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same work in 2 days, then what is the time taken by 15 men and 20 boys to complete the same type of work?

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