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If the radius of each of four outer circles is \(r\), then the radius of the innermost circle is

Question and options

If the radius of each of four outer circles is rr, then the radius of the innermost circle is

Figure

  1. 22+1r\frac{\sqrt{2}}{\sqrt{2+1}} r
  2. 12r\frac{1}{\sqrt{2}} r
  3. (2−1)r(\sqrt{2}-1) r
  4. 2r\sqrt{2 r}

Answer and explanation

Correct answer: C - \((\sqrt{2}-1) r\)
The centres of the outer circles form a square of side 2r, with diagonal 2sqrt(2) r. Centre to outer centre = sqrt(2) r, so the inner radius = sqrt(2) r - r = (sqrt(2)-1) r.

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