Find the missing term in the following series: \(6,8,4,6,3,5, ?, \frac{9}{2}, \ldots\)
Question and options
Find the missing term in the following series:
- 8
- 3
Answer and explanation
Correct answer: C - \(\frac52\)
The pattern alternates +2 and /2: 6+2=8, 8/2=4, 4+2=6, 6/2=3, 3+2=5, 5/2=5/2, then 5/2+2=9/2. Missing term is 5/2.
Practice for these exams
-
JIPMAT
Related question papers
Related exam syllabi
More solved explanations in Number series & simplification
- Consider the following pattern. \(2^2 + 1 = 5\), \(3^2 + 1 = 10\), \(4^2 + 1 = 17\), \(5^2 + 1 = 26\) Using the given pattern find the value of \(x\) in \(x^2 + 1…
- The value of ‘A’ in the expression 5 + 12 × 10 ÷ 120/240 = A × 10 is:
- Which number is real in the following?
- The sum up to \(10\) terms of the series \(1 \cdot 3 + 5 \cdot 7 + 9 \cdot 11 + ...\) is
- The roots of the equation ax^2 + bx + c = 0 (where a ≠ 0 and c ≠ 0) are: