Consider the following pattern.
$2^2 + 1 = 5$ , $3^2 + 1 = 10$ , $4^2 + 1 = 17$ , $5^2 + 1 = 26$
Using the given pattern find the value of $x$ in $x^2 + 1 = 170$ .

Question

Consider the following pattern. $2^2 + 1 = 5$, $3^2 + 1 = 10$, $4^2 + 1 = 17$, $5^2 + 1 = 26$ Using the given pattern find the value of $x$ in $x^2 + 1 = 170$.

Accepted Answer

D - 13. The pattern is $n^2 + 1$: $2^2+1=5$, $3^2+1=10$, $4^2+1=17$, $5^2+1=26$. $x^2 + 1 = 170$ gives $x^2 = 169$, so $x = 13$.

Answer

A - 12

Answer

B - 15

Answer

C - 14

Consider the following pattern. \(2^2 + 1 = 5\), \(3^2 + 1 = 10\), \(4^2 + 1 = 17\), \(5^2 + 1 = 26\) Using the given pattern find the value of \(x\) in \(x^2 + 1 = 170\).

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