Consider the polynomials \(f(x) = ax^2 + bx + c\), where \(a > 0, b, c\) are real, \(g(x) = -2x\). If \(f(x)\) cuts the x-axis at \((-2, 0)\) and \(g(x)\) passes through \((a, b)\), then the minimum…
Question and options
Consider the polynomials , where are real, . If cuts the x-axis at and passes through , then the minimum value of is
- 0
- 1
- 2
- 3
Answer and explanation
Correct answer: B - 1
g passes through (a,b): b=-2a. f(-2)=0: 4a-2b+c=0 -> 8a+c=0 -> c=-8a. f = a(x^2-2x-8), minimum at x=1 equals -9a. So min of f+9a+1 = 1.
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