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If \(y=a+b \log _{e} x\) then which of the following is true?

Question and options

If y=a+blog⁡exy=a+b \log _{e} x then which of the following is true?
  1. 1y−a\frac{1}{y-a} is proportional to xbx^{b}
  2. y−ay-a is proportional to xbx^{b}
  3. eye^{y} is proportional to xbx^{b}
  4. log⁡ey\log _{e} y is proportional to xx

Answer and explanation

Correct answer: C - \(e^{y}\) is proportional to \(x^{b}\)
y - a = b ln x = ln(x^b), so e^(y-a) = x^b, i.e. e^y = e^a * x^b, so e^y is proportional to x^b.

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