Site navigation

Consider the following two statements, one is labelled as Assertion (A) and the other is labelled as Reason (R). Assertion (A) : The sum of \(n\) terms of the Progression…

Question and options

Consider the following two statements, one is labelled as Assertion (A) and the other is labelled as Reason (R).

Assertion (A) :

The sum of nn terms of the Progression

1+12+122+123+⋯1+\frac{1}{2}+\frac{1}{2^{2}}+\frac{1}{2^{3}}+\cdots is 2n−1−12n−1\frac{2^{n-1}-1}{2^{n-1}}.

Reason (R) :

Sum of a geometric series having nn terms is given by Sn=a(1−rn)1−rS_{n}=\frac{a\left(1-r^{n}\right)}{1-r}, where aa is the 1st 1^{\text {st }} term and rr is the common ratio.
  1. Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of (A).
  2. Both Assertion (A) and Reason (R) are true but Reason (R) is NOT the correct explanation of (A).
  3. (A) is true but (R) is false.
  4. (A) is false but (R) is true.

Answer and explanation

Correct answer: D - (A) is false but (R) is true.
With a=1 and r=1/2, S_n = (1-(1/2)^n)/(1/2) = (2^n-1)/2^(n-1), not (2^(n-1)-1)/2^(n-1). So A is false; R is the correct GP sum formula.

Practice for these exams

  • JIPMAT

Related question papers

Related exam syllabi

More solved explanations in Arithmetic