Ayesha is standing atop a vertical tower \(200 m\) high and observes a car moving away from the tower on a straight, horizontal road from the foot of the tower. At 11:00 AM, she observes the angle…
Question and options
Ayesha is standing atop a vertical tower high and observes a car moving away from the tower on a straight, horizontal road from the foot of the tower. At 11:00 AM, she observes the angle of depression of the car to be . At 11:02 AM, she observes the angle of depression of the car to be . The speed at which the car is moving is approximately
- 6.3 km per hour
- 8.45 km per hour
- 10.6 km per hour
- 4.39 km per hour
Answer and explanation
Correct answer: D - 4.39 km per hour
Distances from foot: 200 cot45=200 m, 200 cot30=200sqrt(3)=346.41 m. Car moves 146.41 m in 2 min = 73.2 m/min = 4.39 km/h.
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IPMAT Indore
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