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The maximum value of the natural number \(n\) for which \(21^n\) divides \(50!\) is

Question and options

The maximum value of the natural number nn for which 21n21^n divides 50!50! is
  1. 6
  2. 7
  3. 8
  4. 9

Answer and explanation

Correct answer: C - 8
21 = 3*7. Power of 7 in 50! = 7+1 = 8; power of 3 = 16+5+1 = 22. Limiting factor is 7, so n = 8.

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  • IPMAT Indore

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