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A train travels at a certain average speed for a distance of 63 km and then travels a distance of 72 km at an average speed of 6 km/hr more than its original speed. If it takes 3 hours to complete…

Question and options

A train travels at a certain average speed for a distance of 63 km and then travels a distance of 72 km at an average speed of 6 km/hr more than its original speed. If it takes 3 hours to complete the total journey, what is the original speed of the train in km/hr?
  1. 24
  2. 33
  3. 42
  4. 66

Answer and explanation

Correct answer: C - 42
Let speed be vv: 63v+72v+6=3\frac{63}{v} + \frac{72}{v+6} = 3. Testing v=42v = 42: 6342=1.5\frac{63}{42} = 1.5 and 7248=1.5\frac{72}{48} = 1.5, total 3 hours. So the original speed is 42 km/h.

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