Which of the following are correct in case of theory of sets. (A ∪ B′) ∩ (A′ ∪ C) ∩ (B ∪ C′) = (A ∩ B ∩…

The three clauses on the left imply A⇒C⇒B⇒A, so membership is possible only when all three indicators are 1 or all are 0. Thus the expression is (A∩B∩C)∪(A′∩B′∩C′), validating B and E by De Morgan’s law. C is the distributive law. A incorrectly includes every member of the union; D incorrectly substitutes a union-type distribution for intersection. The correct set is B, C and E.