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Transmission of N signals, each band limited to fm Hz by TDM, requires a minimum band-width of :

By the Nyquist criterion, each signal band-limited to \(f_m\) must be sampled at least \(2f_m\) times a second, so N multiplexed signals give \(2Nf_m\) samples a second. A…

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Transmission of N signals, each band limited to fm Hz by TDM, requires a minimum band-width of :

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Correct answer C

By the Nyquist criterion, each signal band-limited to fmf_m must be sampled at least 2fm2f_m times a second, so N multiplexed signals give 2Nfm2Nf_m samples a second. A channel of bandwidth B can carry at most 2B pulses a second without intersymbol interference, so the minimum bandwidth is 2Nfm/2=Nfm2Nf_m / 2 = Nf_m. The figure 2Nfm2Nf_m is the combined sampling rate, not the bandwidth.

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  • UGC NET Computer Science and Applications

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