The time delays of the four segments in the pipeline are as follows : t1 = 50 ns, t2 = 30 ns, t3 = 95…
The total time is 10300 ns. The pipeline clock period is the longest segment delay plus the interface delay, \(95+5=100\) ns. Four stages and 100 tasks require…
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The time delays of the four segments in the pipeline are as follows : t1 = 50 ns, t2 = 30 ns, t3 = 95 ns and t4 = 45 ns. The interface delay time tr = 5 ns. How long will it take to complete 100 tasks in the pipeline ?
Answer and explanation
Correct answer B
The total time is 10300 ns. The pipeline clock period is the longest segment delay plus the interface delay, ns. Four stages and 100 tasks require cycles, giving ns.
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Himachal Pradesh SET (HP SET)