Position of points O(0,0) and P(2,−3) in the region of graph of inequation2x−3y<5 will be:
Substitute each point into \(2x - 3y < 5\). At O(0, 0) the left side is 0, which is less than 5, so O lies inside the region. At P(2, −3) it is \(4 + 9 = 13\), which is not…
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Position of points O(0,0) and P(2,−3) in the region of graph of inequation2x−3y<5 will be:
Answer and explanation
Correct answer A
Substitute each point into . At O(0, 0) the left side is 0, which is less than 5, so O lies inside the region. At P(2, −3) it is , which is not less than 5, so P lies outside.
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UGC NET Economics