Match the following : List - IList - II (a) (p→q)⇔(¬q→¬p) (i) Contrapositive (b) [(p∧q)→r]⇔[p→(q→r)]…
\((p\to q)\Leftrightarrow(\neg q\to\neg p)\) is the contrapositive law (i); \([(p\wedge q)\to r]\Leftrightarrow[p\to(q\to r)]\) is the exportation law (ii); \((p\to…
Choose your answer
Match the following :
| List - I | List - II |
|---|---|
| (a) (p→q)⇔(¬q→¬p) | (i) Contrapositive |
| (b) [(p∧q)→r]⇔[p→(q→r)] | (ii) Exportation law |
| (c) (p→q)⇔[(p∧¬q)→o] | (iii) Reductio ad absurdum |
| (d) (p↔q)⇔[(p→q)∧(q→p)] | (iv) Equivalence |
Codes : (a), (b), (c), (d)
Answer and explanation
Correct answer A
is the contrapositive law (i); is the exportation law (ii); , where o is a contradiction, is reductio ad absurdum (iii), since assuming p and not-q leads to falsity; and defines equivalence (iv). The code is (i), (ii), (iii), (iv).
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UGC NET Computer Science and Applications