In a population of men in a city, 13% are observed to suffer from cancer, 15% are found to be smokers,…

Let C denote the event that a randomly selected man suffers from cancer, and S denote the event that he is a smoker. From the given information: - P(C) = 13% = 0.13 - P(S) = 15% = 0.15 - P(C ∪ S) = 20% = 0.20 By the addition rule of probability for two events: P(C ∪ S) = P(C) + P(S) - P(C ∩ S) Rearranging to solve for the probability that the man is both a smoker and suffering from cancer, P(C ∩ S): P(C ∩ S) = P(C) + P(S) - P(C ∪ S) = 0.13 + 0.15 - 0.20 = 0.28 - 0.20 = 0.08. Therefore, (0.08) is the correct answer.