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If the mean of n numbers of a series is x̄ and the sum of first (n-1) numbers is λ, then the last…

The sum of all \(n\) numbers is \(n\bar{x}\). Since the sum of the first \((n-1)\) numbers is \(\lambda\), the last number is \(n\bar{x} - \lambda\).

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If the mean of n numbers of a series is x̄ and the sum of first (n-1) numbers is λ, then the last number of the series is-

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Correct answer B

The sum of all nn numbers is nxˉn\bar{x}. Since the sum of the first (n−1)(n-1) numbers is λ\lambda, the last number is nxˉ−λn\bar{x} - \lambda.

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