If n and r are non-negative integers and n ≥ r, then p(n + 1, r) equals to
P(n+1, r)/P(n, r)=[(n+1)!/(n+1-r)!]/[n!/(n-r)!]=(n+1)/(n+1-r). This also holds for r0; given n>=r, denominator is positive. Other numerator/denominator shifts do not cancel…
Choose your answer
If n and r are non-negative integers and n ≥ r, then p(n + 1, r) equals to
Answer and explanation
Correct answer A
P(n+1, r)/P(n, r)=[(n+1)!/(n+1-r)!]/[n!/(n-r)!]=(n+1)/(n+1-r). This also holds for r0; given n>=r, denominator is positive. Other numerator/denominator shifts do not cancel the factorials properly.
Practice for these exams
-
UGC NET Computer Science and Applications