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For the equations C = 0.8(1 – t)y, t = 0.25, I = 900 – 50i, G = 800, L = 0.25y – 62.5i, M = 500 (usual…

The aggregate demand function is \(0.75y=2125+500/P\). Since \(C=0.8(0.75)y=0.6y\), goods-market equilibrium gives \(0.4y=1700-50i\). Money-market equilibrium gives…

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For the equations C = 0.8(1 – t)y, t = 0.25, I = 900 – 50i, G = 800, L = 0.25y – 62.5i, M = 500 (usual notations apply), the aggregate demand function is:

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The aggregate demand function is 0.75y=2125+500/P0.75y=2125+500/P. Since C=0.8(0.75)y=0.6yC=0.8(0.75)y=0.6y, goods-market equilibrium gives 0.4y=1700−50i0.4y=1700-50i. Money-market equilibrium gives 500/P=0.25y−62.5i500/P=0.25y-62.5i, or 50i=0.2y−400/P50i=0.2y-400/P. Substitution gives 0.6y=1700+400/P0.6y=1700+400/P; multiplying by 1.251.25 yields 0.75y=2125+500/P0.75y=2125+500/P.

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  • West Bengal SET (WB SET)

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