Food X contains 6 units of Vitamin D per gram and 7 units of Vitamin E per gram and cost is Rs 12 per…
The corner points of the feasible region are (0, 12.5), the intersection of the two constraint lines, and (120/7, 0). Solving \(6x + 8y = 100\) and \(7x + 12y = 120\) gives…
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Food X contains 6 units of Vitamin D per gram and 7 units of Vitamin E per gram and cost is Rs 12 per gram. Food Y contains 8 units of vitamin D per gram and 12 units of Vitamin E per gram and cost is Rs 20 per gram. The daily minimum requirements of vitamin D and E are 100 units and 120 units respectively. Suppose x is quantity (in gram) of food X, y is quantity (in gram) of food Y. Answering the following question based on the above paragraph given.
Which of the following are quantities (in grams) of food X and Y respectively when the cost of food is minimum :
Answer and explanation
Correct answer B
The corner points of the feasible region are (0, 12.5), the intersection of the two constraint lines, and (120/7, 0). Solving and gives x = 15 and y = 5/4, with cost . The other corners cost 250 and , so (15, 5/4) is the minimum; the point (0, 10) is not even feasible, since it gives only 80 units of vitamin D.
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UGC NET Computer Science and Applications