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A speaks truth in 75% cases and B in 80% cases. In what percentage of cases, they are likely to…

They are likely to contradict each other in 35% of cases. Exactly one speaks the truth while the other does not, so the probability is \((0.75\times0.20)+(0.25\times0.80)\)…

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A speaks truth in 75% cases and B in 80% cases. In what percentage of cases, they are likely to contradict each other while narrating the same incident ?

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Correct answer D

They are likely to contradict each other in 35% of cases. Exactly one speaks the truth while the other does not, so the probability is (0.75×0.20)+(0.25×0.80)(0.75\times0.20)+(0.25\times0.80) =0.15+0.20=0.15+0.20 =0.35=0.35, which corresponds to 35%.

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