A population of size 400, consists of 123 copies of genome 0001 (with fitness 0.12), 57 copies of…
The estimated fitness is approximately 0.4871. The schema \(1***\) matches 1111 and 1010, so its average fitness is \(\frac{57(0.23)+201(0.56)}{57+201}\)…
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A population of size 400, consists of 123 copies of genome 0001 (with fitness 0.12), 57 copies of genome 1111 (with fitness 0.23), 201 copies of genome 1010 (with fitness 0.56) and 19 copies of genome 0110 (with fitness 0.43). What is approximately the estimated fitness of schema 1 *** ?
Answer and explanation
Correct answer A
The estimated fitness is approximately 0.4871. The schema matches 1111 and 1010, so its average fitness is .
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Maharashtra and Goa SET (MH SET)