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A block of addresses is granted to a small organization. If one of the address is 205.16.37.39/28. What…

For the /28 CIDR block containing 205.16.37.39, the number of host bits is \(32 - 28 = 4\), giving \(2^4 = 16\) total addresses in the block. Since \(39 = 2 \times 16 + 7\),…

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A block of addresses is granted to a small organization. If one of the address is 205.16.37.39/28. What is the value of first address and total number of addresses in the block ?

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For the /28 CIDR block containing 205.16.37.39, the number of host bits is 32−28=432 - 28 = 4, giving 24=162^4 = 16 total addresses in the block. Since 39=2×16+739 = 2 \times 16 + 7, the block starts at the multiple of 16, which is 205.16.37.32.

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