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Out of 80 players 35 play cricket, 42 play hockey, 25 play football, 8 play both cricket and hockey, 10…

16 players play exactly two games. Removing the three who play all games from each pair gives \(8-3=5\), \(10-3=7\), and \(7-3=4\). These disjoint groups total \(5+7+4=16\).

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Out of 80 players 35 play cricket, 42 play hockey, 25 play football, 8 play both cricket and hockey, 10 play both cricket and football, 7 play both hockey and football, 3 play all the three games.

How many players play exactly two games ?

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Correct answer D

16 players play exactly two games. Removing the three who play all games from each pair gives 8−3=58-3=5, 10−3=710-3=7, and 7−3=47-3=4. These disjoint groups total 5+7+4=165+7+4=16.

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