Site navigation

Which of the following straight lines are both tangent to the circle \(x ^ 2 + y ^ 2 - 6x + 4y - 12 = 0\)?

Question and options

Which of the following straight lines are both tangent to the circle x2+y2−6x+4y−12=0x ^ 2 + y ^ 2 - 6x + 4y - 12 = 0?
  1. 4x+3y+19=0,4x+3y−31=04x+3y+19=0, 4x+3y-31=0
  2. 4x+3y−19=0,4x+3y+31=04x+3y-19=0, 4x+3y+31=0
  3. 4x+3y−19=0,4x+3y−31=04x+3y-19=0, 4x+3y-31=0
  4. 4x+3y+19=0,4x+3y+31=04x+3y+19=0, 4x+3y+31=0

Answer and explanation

Correct answer: A - \(4x+3y+19=0, 4x+3y-31=0\)
Centre (3,-2), r^2=9+4+12=25, r=5. For 4x+3y+c=0, distance |12-6+c|/5 = 5 gives |6+c|=25, so c=19 or c=-31: 4x+3y+19=0 and 4x+3y-31=0.

Practice for these exams

  • IPMAT Indore

Related question papers

Related exam syllabi

More solved explanations in Arithmetic