What least number must be subtracted from each of the numbers 14, 17, 34 and 42 so that the remainders may be proportional?
Question and options
What least number must be subtracted from each of the numbers 14, 17, 34 and 42 so that the remainders may be proportional?
- 0
- 1
- 2
- 7
Answer and explanation
Correct answer: C - 2
Need (14-x)/(17-x) = (34-x)/(42-x). Cross-multiplying: 588 - 56x = 578 - 51x, so 5x = 10, x = 2 (12:15 = 32:40 = 4:5).
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CUSAT Three-Year LL.B.
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