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Two taps A and B can fill a tank in 10 hours and 15 hours respectively. Both the taps are opened for 4 hours and then B is turned off. The time taken by A to fill the remaining tank is

Question and options

Two taps A and B can fill a tank in 10 hours and 15 hours respectively. Both the taps are opened for 4 hours and then B is turned off. The time taken by A to fill the remaining tank is
  1. 125\frac{12}{5} hours
  2. 1310\frac{13}{10} hours
  3. 6 hours
  4. 103\frac{10}{3} hours

Answer and explanation

Correct answer: D - \(\frac{10}{3}\) hours
Together A and B fill 110+115=16\frac{1}{10}+\frac{1}{15}=\frac{1}{6} per hour, so in 4 hours 23\frac{2}{3} is filled. The remaining 13\frac{1}{3} at A's rate of 110\frac{1}{10} per hour takes 103\frac{10}{3} hours.

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