Two statements are given: Statement I: In $\triangle A B C, A B=6 \sqrt{3} \mathrm{~cm}, A C=12 \mathrm{~cm}$ and $B C=6 \mathrm{~cm}$, then angle $B=90^{\circ}$ Statement II: \(\triangle A B…

Question

Two statements are given:

Statement I: In

\triangle A B C, A B=6 \sqrt{3} \mathrm{~cm}, A C=12 \mathrm{~cm}

and

B C=6 \mathrm{~cm}

, then angle

B=90^{\circ}

Statement II:

\triangle A B C

is isosceles with

A C=B C

. If

A B^{2}=2 AC^{2}

, Then angle

C=90^{\circ}

In the light of the given statements, choose the correct answer from the given options:

Accepted Answer

A - Both Statement I and Statement II are true. I: AB^2 + BC^2 = 108 + 36 = 144 = AC^2, so angle B = 90 deg (true). II: AB^2 = 2AC^2 = AC^2 + BC^2, so angle C = 90 deg (true).

Answer

B - Both Statement I and Statement II are false

Answer

C - Statement I is true but Statement II is false

Answer

D - Statement I is false but Statement II is true

Two statements are given: Statement I: In \(\triangle A B C, A B=6 \sqrt{3} \mathrm{~cm}, A C=12 \mathrm{~cm}\) and \(B C=6 \mathrm{~cm}\), then angle \(B=90^{\circ}\) Statement II: \(\triangle A B…

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