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Two monochromatic light beams of intensities I and 4I are superposed. The maximum and minimum possible intensities in the resulting beam are

Question and options

Two monochromatic light beams of intensities I and 4I are superposed. The maximum and minimum possible intensities in the resulting beam are
  1. 5I and I
  2. 5I and 3I
  3. 9I and I
  4. 9I and 3I

Answer and explanation

Correct answer: C - 9I and I
Amplitudes go as I\sqrt{I}: a and 2a. Imax=(a+2a)2=9II_{\mathrm{max}} = (a+2a)^2 = 9I, Imin=(2a−a)2=II_{\mathrm{min}} = (2a-a)^2 = I.

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