Three cubes with integer edge lengths are given. It is known that the sum of their surface areas is $564 \ \text{cm}^2$. Then the possible values of the sum of their volumes are

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A - $764 \ \text{cm}^3$ and $586 \ \text{cm}^3$. 6(a^2+b^2+c^2) = 564 gives a^2+b^2+c^2 = 94; integer solutions are (9,3,2) and (7,6,3). Volumes: 729+27+8 = 764 and 343+216+27 = 586.

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B - $586 \ \text{cm}^3$ and $564 \ \text{cm}^3$

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C - $764 \ \text{cm}^3$ and $564 \ \text{cm}^3$

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D - $586 \ \text{cm}^3$ and $786 \ \text{cm}^3$

Three cubes with integer edge lengths are given. It is known that the sum of their surface areas is \(564 \ \text{cm}^2\). Then the possible values of the sum of their volumes are

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