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The x-intercept of the line that passes through the intersection of the lines \(x + 2y = 4\) and \(2x + 3y = 6\), and is perpendicular to the line \(3x - y = 2\) is

Question and options

The x-intercept of the line that passes through the intersection of the lines x+2y=4x + 2y = 4 and 2x+3y=62x + 3y = 6, and is perpendicular to the line 3x−y=23x - y = 2 is
  1. 2
  2. 0.5
  3. 4
  4. 6

Answer and explanation

Correct answer: D - 6
Intersection of x+2y=4 and 2x+3y=6 is (0,2). Line 3x-y=2 has slope 3, so required slope -1/3: y = 2 - x/3. Setting y=0 gives x = 6.

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  • IPMAT Indore

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