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The wavelength associated with an electron (\(m_e = 9.1 \times 10^{-31}\ \mathrm{kg}\)) moving with a velocity of \(10^3\ \mathrm{m/s}\) is

Question and options

The wavelength associated with an electron (me=9.1×10−31 kgm_e = 9.1 \times 10^{-31}\ \mathrm{kg}) moving with a velocity of 103 m/s10^3\ \mathrm{m/s} is
  1. 7253 Å
  2. 7253 m
  3. 725.3 Å
  4. 8000 m

Answer and explanation

Correct answer: A - 7253 Å
λ=hmv=6.6×10−349.1×10−31×103=7.25×10−7 m\lambda = \frac{h}{mv} = \frac{6.6 \times 10^{-34}}{9.1 \times 10^{-31} \times 10^3} = 7.25 \times 10^{-7}\ \mathrm{m}, about 7253 Å.

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